Next we’ll continue to practice with inheritance. We’ll also introduce a new big (literally) idea—polymorphism. Polymorphism may sound scary, but it’s not, and we’ll work it out together like we always do, using a lot of examples.
Let’s look at another example of puzzling Java code together:
Polymorphism is a big word, and sounds a bit scary. But it’s actually quite straightforward. Let’s work it out together starting with the Wikipedia definition:
In programming languages and type theory, polymorphism is the provision of a single interface to entities of different types
One way to think about polymorphism and Java inheritance is to consider “is a” relationships.
For example, every instance of any Java class “is a” Object, because every class is a subclass of Object.
Other “is a” relationships depend on inheritance relationships established with extends:
One frequent confusion regarding polymorphism has to do with overriding inherited methods. Let’s look at how that works:
When we create an instance of a class, we can save it into a variable of any type that it can morph into:
This is referred to as upcasting.
Java will automatically upcast an instance to any of its supertypes.
Because Dog extends Pet and Pet extends Object, a Dog can be stored in a Dog, Pet, or Object variable.
However! The type of the variable determines what we can do with that object. Let’s look at how.
Don’t worry if this seems a bit fuzzy now. We’ll return to this topic a few lessons from now when we discuss object references.
instanceofinstanceofConsider the type hierarchy established below:
Given a Pet variable, it might refer to a Dog, a Cat, a Pet or some other kind of pet!
Is there a way that we can tell?
Yup!
To test if an object is an instance of a particular class, we use the instanceof operator.
And, once we determine that cat is actually an instance of Cat, there is another step that we have to take before we can call meow.
Let’s examine how that works:
Create a public class named Greeter that provides a single class method named
greet.
greet should accept a single parameter, a Person to greet, and return a String, the greeting.
Depending on what kind of person it is, you should greet them differently:
Professor—for instance, one named "Geoff"—you should greet them "Hi Professor Geoff"Student—for instance, one named "Friendly"—you should greet them "Hey Friendly, you are not
alone!"Staff, then they will have a String role you can retrieve using getRole.
For example, if their role is "advising" their name is "Chuchu", you should greet them "Thanks Chuchu for all your
help with advising".All Persons have a name that you can retrieve using getName.
If the person is null or not one of the kinds of people described above, return null.
Do not solve this problem using method overloading.
And do not hard-code the answers.
Your solution should work for any Professor, Student, or Staff.
The last two lessons have been pretty loaded with new ideas and concepts! Exciting, but also enough to make your head spin.
Don’t worry. Over the next two lessons we’ll slow down and review what we’ve learned. And then, over the lessons that follow we’ll have even more opportunities to integrate this knowledge, but with a small twist. So be patient. This won’t all make sense immediately. But it will all make sense eventually.
Create a public class named Orderer that provides a single class method named
order.
order should accept a single parameter, a Restaurant to order from, and return a String, a comment on your
order.
Depending on which subclass of Restaurant it is, you should respond differently:
Fancy restaurant—for instance, with name "MIGA"—you should order "At MIGA I'll order
something
inexpensive"FastFood restaurant, for instance, with with name "Chipotle"—you should order "At
Chipotle I'll order
something healthy"Vegan restaurant, then it will have a String property cuisine you can retrieve
using getCuisine.
For example, if it its cuisine is "Thai" and name is "Vegan Delight", you should order "At Vegan Delight I'll
order delicious Thai
food".All Restaurants have a name that you can retrieve using getName.
If the restaurant is null or not one of the kinds described above, return null.
Do not solve this problem using method overloading.
And do not hard-code the answers.
Your solution should work for any Fancy, FastFood, or Vegan instance.
Note that we are not implying that there are not fancy vegan restaurants or fancy fast food restaurants or vegan fast-food restaurants. If anything, the ability of real entities to resist strict classification is one of the limitations of Java's object model.
Need more practice? Head over to the practice page.