Solve: Easy Peasy Loop

Created By: Geoffrey Challen

/ Version: 2020.9.0

Assuming an int variable named count has been declared and initialized to a value larger than or equal to 0, write a snippet of code (not a function) that alternately prints "peasy" and "easy" on subsequent lines a total of count times. So if count is 7, you should print:

peasy
easy
peasy
easy
peasy
easy
peasy

Note that you can test if a number is even by using the remainder operator: n % 2 == 0.